To solve this problem, we need to understand that the second car started an hour later than the first car but still arrived at the destination at the same time. This means the second car must have been traveling faster to cover the same distance in less time.

1. Let's assume the first car traveled for exactly 6 hours. Since they both arrived at the same time, this means the second car traveled for 5 hours.

2. The speed of a vehicle is given by the distance divided by the time. Since both cars traveled the same distance, we can say that the speed is inversely proportional to the time.

3. Therefore, the ratio of the speeds of the first car to the second car is the same as the ratio of the times for the second car to the first car. This can be written as Speed1/Speed2 = Time2/Time1.

4. Substituting the given times into the equation gives us Speed1/Speed2 = 5/6.

5. To find the percentage by which the speed of the second car is greater than the speed of the first car, we subtract the speed of the first car from the speed of the second car, divide by the speed of the first car, and then multiply by 100. This can be written as ((Speed2 - Speed1) / Speed1) * 100.

6. Substituting Speed1/Speed2 = 5/6 into the equation gives us ((6/5*Speed1 - Speed1) / Speed1) * 100 = 20%.

So, the highest possible value of the percentage by which the speed of the second car could exceed that of the first car is 20%.

Question

To solve this problem, we need to understand that the second car started an hour later than the first car but still arrived at the destination at the same time. This means the second car must have been traveling faster to cover the same distance in less time.

1. Let's assume the first car traveled for exactly 6 hours. Since they both arrived at the same time, this means the second car traveled for 5 hours.

2. The speed of a vehicle is given by the distance divided by the time. Since both cars traveled the same distance, we can say that the speed is inversely proportional to the time.

3. Therefore, the ratio of the speeds of the first car to the second car is the same as the ratio of the times for the second car to the first car. This can be written as Speed1/Speed2 = Time2/Time1.

4. Substituting the given times into the equation gives us Speed1/Speed2 = 5/6.

5. To find the percentage by which the speed of the second car is greater than the speed of the first car, we subtract the speed of the first car from the speed of the second car, divide by the speed of the first car, and then multiply by 100. This can be written as ((Speed2 - Speed1) / Speed1) * 100.

6. Substituting Speed1/Speed2 = 5/6 into the equation gives us ((6/5*Speed1 - Speed1) / Speed1) * 100 = 20%.

So, the highest possible value of the percentage by which the speed of the second car could exceed that of the first car is 20%.

Knowee AI · Accepted Answer