Perform the indicated operations.$7\left(\begin{bmatrix}-1&0\\8&-4\\-3&5\end{bmatrix}-\begin{bmatrix}4&3\\6&0\\5&1\end{bmatrix}\right)=$7([−1 08 −4−3 5]−[4 36 05 1])=​

First, we need to subtract the two matrices:

$\begin{bmatrix}-1&0\\8&-4\\-3&5\end{bmatrix}-\begin{bmatrix}4&3\\6&0\\5&1\end{bmatrix} = \begin{bmatrix}-1-4&0-3\\8-6&-4-0\\-3-5&5-1\end{bmatrix}$

This simplifies to:

$\begin{bmatrix}-5&-3\\2&-4\\-8&4\end{bmatrix}$

Next, we multiply this matrix by 7:

$7*\begin{bmatrix}-5&-3\\2&-4\\-8&4\end{bmatrix} = \begin{bmatrix}-35&-21\\14&-28\\-56&28\end{bmatrix}$

So, $7\left(\begin{bmatrix}-1&0\\8&-4\\-3&5\end{bmatrix}-\begin{bmatrix}4&3\\6&0\\5&1\end{bmatrix}\right) = \begin{bmatrix}-35&-21\\14&-28\\-56&28\end{bmatrix}$.

First, we need to subtract the two matrices:

$\begin{bmatrix}-1&0\\8&-4\\-3&5\end{bmatrix}-\begin{bmatrix}4&3\\6&0\\5&1\end{bmatrix} = \begin{bmatrix}-1-4&0-3\\8-6&-4-0\\-3-5&5-1\end{bmatrix}$

This simplifies to:

$\begin{bmatrix}-5&-3\\2&-4\\-8&4\end{bmatrix}$

Next, we multiply this matrix by 7:

$7*\begin{bmatrix}-5&-3\\2&-4\\-8&4\end{bmatrix} = \begin{bmatrix}7*-5&7*-3\\7*2&7*-4\\7*-8&7*4\end{bmatrix}$

This simplifies to:

$\begin{bmatrix}-35&-21\\14&-28\\-56&28\end{bmatrix}$

So, $