Work done in moving a 50 kg block through a horizontal distance of 10 m by applying a force of 100 N which makes an angle of 60o with the horizontal isA 200 joule B 425 joule C 500 joule D 575 joule
Question
Work done in moving a 50 kg block through a horizontal distance of 10 m by applying a force of 100 N which makes an angle of 60o with the horizontal isA 200 joule B 425 joule C 500 joule D 575 joule
Solution
To calculate the work done in moving the block, we can use the formula:
Work = Force * Distance * cos(theta)
Where:
- Force is the applied force (100 N)
- Distance is the horizontal distance (10 m)
- theta is the angle between the force and the horizontal (60 degrees)
First, we need to find the horizontal component of the force. We can do this by multiplying the force by the cosine of the angle:
Horizontal component of force = Force * cos(theta) = 100 N * cos(60 degrees) = 100 N * 0.5 = 50 N
Now, we can calculate the work done:
Work = Force * Distance * cos(theta) = 50 N * 10 m * cos(60 degrees) = 500 Nm * 0.5 = 250 J
Therefore, the work done in moving the block is 250 joules.
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