To determine the phenotype ratio of the offspring, we need to understand the principles of inheritance for coat color in guinea pigs. In this case, black coat color is dominant over white coat color.

The parents in question are both heterozygous black guinea pigs, which means they carry one dominant black allele (B) and one recessive white allele (b). When these two parents mate, they can produce offspring with different combinations of these alleles.

To determine the possible phenotypes of the offspring, we can use a Punnett square. Let's represent the black allele as B and the white allele as b.

The Punnett square for this mating would look like this:

B b
-----------------
B | BB Bb
-----------------
b | Bb bb

From the Punnett square, we can see that there are four possible genotypes for the offspring: BB, Bb, Bb, and bb.

However, since black coat color is dominant, any offspring with at least one black allele (BB or Bb) will have a black phenotype. Only offspring with two white alleles (bb) will have a white phenotype.

Therefore, the phenotype ratio of the offspring would be three black to one white, which corresponds to option (3) in the given choices: three black to one white.

Question

To determine the phenotype ratio of the offspring, we need to understand the principles of inheritance for coat color in guinea pigs. In this case, black coat color is dominant over white coat color.

The parents in question are both heterozygous black guinea pigs, which means they carry one dominant black allele (B) and one recessive white allele (b). When these two parents mate, they can produce offspring with different combinations of these alleles.

To determine the possible phenotypes of the offspring, we can use a Punnett square. Let's represent the black allele as B and the white allele as b.

The Punnett square for this mating would look like this:

B       b
    -----------------
B |   BB     Bb
    -----------------
b |   Bb     bb

From the Punnett square, we can see that there are four possible genotypes for the offspring: BB, Bb, Bb, and bb.

However, since black coat color is dominant, any offspring with at least one black allele (BB or Bb) will have a black phenotype. Only offspring with two white alleles (bb) will have a white phenotype.

Therefore, the phenotype ratio of the offspring would be three black to one white, which corresponds to option (3) in the given choices: three black to one white.

Knowee AI · Accepted Answer

To determine the phenotype ratio of the offspring, we need to understand the principles of inheritance for coat color in guinea pigs. In this case, black coat color is dominant over white coat color.

The parents in question are both heterozygous black guinea pigs, which means they carry one dominant black allele (B) and one recessive white allele (b). When these two parents mate, they can produce offspring with different combinations of these alleles.

To determine the possible phenotypes of the offspring, we can use a Punnett square. Let's represent the black allele as B and the white allele as b.

The Punnett square for this mating would look like this:

B       b
    -----------------
B |   BB     Bb
    -----------------
b |   Bb     bb

From the Punnett square, we can see that there are four possible genotypes for the offspring: BB, Bb, Bb, and bb.

However, since black coat color is dominant, any offspring with at least one black allele (BB or Bb) will have a black phenotype. Only offspring with two white alleles (bb) will have a white phenotype.

Therefore, the phenotype ratio of the offspring would be three black to one white, which corresponds to option (3) in the given choices: three black to one white.

In guinea pigs, black coat color is dominant over white coat color. The offspring of a mat- ing between two heterozygous black guinea pigs would probably show a phenotype ratio of (1) two black to two white (2) one black to three white (3) three black to one white (4) four black to zero white

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