The offspring of a mating between two heterozygous black guinea pigs would probably show a genotype ratio of (1) 1 BB: 2 Bb: 1 bb (2) 3 Bb: 1 bb (3) 2 BB : 2 bb (4) 2 BB: 1 Bb: 1 bb.

To determine the genotype ratio of the offspring, we need to understand the inheritance pattern of the black coat color in guinea pigs. In this case, "B" represents the dominant allele for black coat color, and "b" represents the recessive allele for non-black coat color.

When two heterozygous black guinea pigs mate, they both carry one dominant allele (B) and one recessive allele (b) for coat color. The possible genotypes of the offspring are BB, Bb, and bb.

Now, let's analyze each option:

(1) 1 BB: 2 Bb: 1 bb - This option suggests that there will be one offspring with the genotype BB, two offspring with the genotype Bb, and one offspring with the genotype bb. This ratio is consistent with Mendelian inheritance, where the dominant allele (B) is expressed in the heterozygous (Bb) and homozygous dominant (BB) genotypes.

(2) 3 Bb: 1 bb - This option suggests that there will be three offspring with the genotype Bb and one offspring with the genotype bb. This ratio does not account for the possibility of homozygous dominant (BB) genotypes.

(3) 2 BB: 2 bb - This option suggests that there will be two offspring with the genotype BB and two offspring with the genotype bb. This ratio does not account for the possibility of heterozygous (Bb) genotypes.

(4) 2 BB: 1 Bb: 1 bb - This option suggests that there will be two offspring with the genotype BB, one offspring with the genotype Bb, and one offspring with the genotype bb. This ratio is consistent with Mendelian inheritance, accounting for all possible genotypes.

Based on the principles of Mendelian inheritance, the most likely genotype ratio for the offspring of a mating between two heterozygous black guinea pigs is (4) 2 BB: 1 Bb: 1 bb.

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The offspring of a mating between two heterozygous black guinea pigs would probably show a genotype ratio of (1) 1 BB: 2 Bb: 1 bb (2) 3 Bb: 1 bb (3) 2 BB : 2 bb (4) 2 BB: 1 Bb: 1 bb.

To determine the genotype ratio of the offspring, we need to understand the inheritance pattern of the black coat color in guinea pigs. In this case, "B" represents the dominant allele for black coat color, and "b" represents the recessive allele for non-black coat color.

When two heterozygous black guinea pigs mate, they both carry one dominant allele (B) and one recessive allele (b) for coat color. The possible genotypes of the offspring are BB, Bb, and bb.

Now, let's analyze each option:

(1) 1 BB: 2 Bb: 1 bb - This option suggests that there will be one offspring with the genotype BB, two offspring with the genotype Bb, and one offspring with the genotype bb. This ratio is consistent with Mendelian inheritance, where the dominant allele (B) is expressed in the heterozygous (Bb) and homozygous dominant (BB) genotypes.

(2) 3 Bb: 1 bb - This option suggests that there will be three offspring with the genotype Bb and one offspring with the genotype bb. This ratio does not account for the possibility of homozygous dominant (BB) genotypes.

(3) 2 BB: 2 bb - This option suggests that there will be two offspring with the genotype BB and two offspring with the genotype bb. This ratio does not account for the possibility of heterozygous (Bb) genotypes.

(4) 2 BB: 1 Bb: 1 bb - This option suggests that there will be two offspring with the genotype BB, one offspring with the genotype Bb, and one offspring with the genotype bb. This ratio is consistent with Mendelian inheritance, accounting for all possible genotypes.

Based on the principles of Mendelian inheritance, the most likely genotype ratio for the offspring of a mating between two heterozygous black guinea pigs is (4) 2 BB: 1 Bb: 1 bb.

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The offspring of a mating between two heterozygous black guinea pigs would probably show a genotype ratio of (1) 1 BB: 2 Bb: 1 bb (2) 3 Bb: 1 bb (3) 2 BB : 2 bb (4) 2 BB: 1 Bb: 1 bb.

To determine the genotype ratio of the offspring, we need to understand the inheritance pattern of the black coat color in guinea pigs. In this case, "B" represents the dominant allele for black coat color, and "b" represents the recessive allele for non-black coat color.

When two heterozygous black guinea pigs mate, they both carry one dominant allele (B) and one recessive allele (b) for coat color. The possible genotypes of the offspring are BB, Bb, and bb.

Now, let's analyze each option:

(1) 1 BB: 2 Bb: 1 bb - This option suggests that there will be one offspring with the genotype BB, two offspring with the genotype Bb, and one offspring with the genotype bb. This ratio is consistent with Mendelian inheritance, where the dominant allele (B) is expressed in the heterozygous (Bb) and homozygous dominant (BB) genotypes.

(2) 3 Bb: 1 bb - This option suggests that there will be three offspring with the genotype Bb and one offspring with the genotype bb. This ratio does not account for the possibility of homozygous dominant (BB) genotypes.

(3) 2 BB: 2 bb - This option suggests that there will be two offspring with the genotype BB and two offspring with the genotype bb. This ratio does not account for the possibility of heterozygous (Bb) genotypes.

(4) 2 BB: 1 Bb: 1 bb - This option suggests that there will be two offspring with the genotype BB, one offspring with the genotype Bb, and one offspring with the genotype bb. This ratio is consistent with Mendelian inheritance, accounting for all possible genotypes.

Based on the principles of Mendelian inheritance, the most likely genotype ratio for the offspring of a mating between two heterozygous black guinea pigs is (4) 2 BB: 1 Bb: 1 bb.

The offspring of a mating between two het- erozygous black guinea pigs would probably show a genotype ratio of (1) 1 BB: 2 Bb: 1 bb (2) 3 Bb: 1 bb (3) 2 BB : 2 bb (4) 2 BB: 1 Bb: 1 bb

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