The potential energy, in Joules, of an object is described by the formulaP.E. = mgh, where m = mass in kg, g = acceleration due to gravity in m/s2, andh = altitude in meters. Find the height above sea level of a 60 kg object with apotential energy equal to 4 × 106 Joules. Assume g = 10 m/s2. Round answer to the nearest meter.

To find the height above sea level of the object, we can rearrange the formula for potential energy to solve for h. The formula is P.E. = mgh, so solving for h gives us h = P.E. / (mg).

Given that the mass m = 60 kg, the acceleration due to gravity g = 10 m/s², and the potential energy P.E. = 4 × 10⁶ Joules, we can substitute these values into the formula:

h = (4 × 10⁶ J) / (60 kg * 10 m/s²) = 6666.67 meters.

Rounding to the nearest meter gives us a height of 6667 meters above sea level.

To find the height above sea level of the object, we can rearrange the formula for potential energy to solve for h. The formula is P.E. = mgh, so solving for h gives us h = P.E. / (mg).

Given that the mass m = 60 kg, the acceleration due to gravity g = 10 m/s², and the potential energy P.E. = 4 × 10⁶ Joules, we can substitute these values into the formula:

h = (4 × 10⁶ J) / (60 kg * 10 m/s²) = 6666.67 meters.

Rounding to the nearest meter gives us a height of 6667 meters above sea level.