Find the intervals on which the function is increasing and the intervals on which the function is decreasing.f(x) = -3x2 + 12x + 36
Question
Find the intervals on which the function is increasing and the intervals on which the function is decreasing.f(x) = -3x2 + 12x + 36
Solution
To find the intervals where the function is increasing or decreasing, we first need to find the derivative of the function.
The derivative of f(x) = -3x^2 + 12x + 36 is f'(x) = -6x + 12.
Next, we set the derivative equal to zero and solve for x to find the critical points:
-6x + 12 = 0 -6x = -12 x = 2
This gives us one critical point at x = 2.
To determine whether the function is increasing or decreasing at these intervals, we test the values in the derivative:
For x < 2, f'(x) = -6x + 12 is positive, so the function is increasing on the interval (-∞, 2).
For x > 2, f'(x) = -6x + 12 is negative, so the function is decreasing on the interval (2, ∞).
So, the function f(x) = -3x^2 + 12x + 36 is increasing on the interval (-∞, 2) and decreasing on the interval (2, ∞).
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