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Calculate the energy required to heat 323.0mg of mercury from −2.9°C to 19.6°C. Assume the specific heat capacity of mercury under these conditions is ·0.139J·g−1K−1 . Round your answer to 3 significant digits.

Question

Calculate the energy required to heat 323.0mg of mercury from −2.9°C to 19.6°C. Assume the specific heat capacity of mercury under these conditions is ·0.139J·g−1K−1 . Round your answer to 3 significant digits.

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Solution

To calculate the energy required to heat a substance, we can use the formula:

q = mcΔT

where:

  • q is the heat energy,
  • m is the mass,
  • c is the specific heat capacity, and
  • ΔT is the change in temperature.

First, we need to convert the mass from milligrams to grams, because the specific heat capacity is given in J/g·K.

323.0 mg = 0.323 g

Next, we calculate the change in temperature. The final temperature is 19.6°C and the initial temperature is -2.9°C, so:

ΔT = T_final - T_initial = 19.6°C - (-2.9°C) = 22.5°C

Now we can substitute these values into the formula:

q = (0.323 g) * (0.139 J/g·K) * (22.5 K) = 1.01 J

So, the energy required to heat 323.0 mg of mercury from -2.9°C to 19.6°C is approximately 1.01 J.

This problem has been solved

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