Calculate the energy required to heat 261.0g of ammonia from 36.8°C to 51.0°C. Assume the specific heat capacity of ammonia under these conditions is ·4.70J·g−1K−1 . Be sure your answer has the correct number of significant digits.
Question
Calculate the energy required to heat 261.0g of ammonia from 36.8°C to 51.0°C. Assume the specific heat capacity of ammonia under these conditions is ·4.70J·g−1K−1 . Be sure your answer has the correct number of significant digits.
Solution
To calculate the energy required to heat a substance, you can use the formula:
q = mcΔT
where:
- q is the heat energy,
- m is the mass of the substance,
- c is the specific heat capacity of the substance, and
- ΔT is the change in temperature.
Given:
- m = 261.0 g,
- c = 4.70 J/g·K, and
- ΔT = 51.0°C - 36.8°C = 14.2 K (Note: a change in temperature of 1°C is equivalent to a change of 1 K).
Substituting these values into the formula gives:
q = (261.0 g) * (4.70 J/g·K) * (14.2 K) = 17278.2 J
However, we need to consider the significant figures in our calculation. The given values have at most four significant figures, so our final answer should also have four significant figures. Therefore, the energy required to heat 261.0 g of ammonia from 36.8°C to 51.0°C is approximately 17280 J.
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