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The average of three numbers is 42. The first is twice the second and the second is twice the third. The difference between the largest and the smallest number is :Select one:a. 36b. 18c. 72d. 54

Question

The average of three numbers is 42. The first is twice the second and the second is twice the third. The difference between the largest and the smallest number is :Select one:a. 36b. 18c. 72d. 54

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Solution

Let's denote the three numbers as x, y, and z.

According to the problem, we know that:

  1. The first number is twice the second, so we can say x = 2y.
  2. The second number is twice the third, so we can say y = 2z.
  3. The average of the three numbers is 42, so we can say (x + y + z) / 3 = 42.

We can substitute x and y from the first two equations into the third equation:

(2y + y + y/2) / 3 = 42 (3.5y) / 3 = 42 y = 42 * 3 / 3.5 y = 36

Substituting y = 36 into x = 2y and y = 2z we get:

x = 2 * 36 = 72 z = 36 / 2 = 18

The difference between the largest and the smallest number is 72 - 18 = 54.

So, the correct answer is d. 54.

This problem has been solved

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