Of the three numbers, the first is twice the second and the second is twice the third. The average of these three numbers is 21. Find the largest numbers.a.47b.38c.48d.36
Question
Of the three numbers, the first is twice the second and the second is twice the third. The average of these three numbers is 21. Find the largest numbers.a.47b.38c.48d.36
Solution
Let's denote the three numbers as x, y, and z.
According to the problem, we know that:
- x = 2y
- y = 2z
We also know that the average of the three numbers is 21, so:
(x + y + z) / 3 = 21 x + y + z = 63
Substituting the first two equations into the third equation, we get:
2y + y + y/2 = 63 3.5y = 63 y = 63 / 3.5 y = 18
Substituting y = 18 into the first equation, we get:
x = 2 * 18 x = 36
So, the largest number is 36. Therefore, the answer is d. 36.
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