Change the following equation of a line into slope-intercept form.𝑦−16=−16𝑥Group of answer choices𝑦=16𝑥+16y = -6x - 1𝑦=−16𝑥−16𝑦=−16𝑥+16y = -6x + 1
Question
Change the following equation of a line into slope-intercept form.𝑦−16=−16𝑥Group of answer choices𝑦=16𝑥+16y = -6x - 1𝑦=−16𝑥−16𝑦=−16𝑥+16y = -6x + 1
Solution
The given equation is y - 16 = -16x. To convert this into slope-intercept form (y = mx + b), we need to isolate y.
Step 1: Add 16 to both sides of the equation to isolate y on one side.
y - 16 + 16 = -16x + 16
This simplifies to:
y = -16x + 16
So, the equation of the line in slope-intercept form is y = -16x + 16.
Similar Questions
Change the following equation of a line into slope-intercept form.y + 18 = -9xGroup of answer choicesy = 9x - 18𝑦=−19𝑥−2y = -9x + 18𝑦=−19𝑥+2y = -9x - 18
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