Sure, here's how you can calculate the work done in accelerating an electron through a potential difference of 220 V:

Step 1: Understand the formula
The work done on a charge q moving through a potential difference V is given by the formula W = qV.

Step 2: Identify the known values
In this case, the charge of an electron (q) is known to be -1.6 x 10^-19 Coulombs and the potential difference (V) is given as 220 V.

Step 3: Substitute the known values into the formula
W = (-1.6 x 10^-19 C) * (220 V)

Step 4: Calculate the result
W = -3.52 x 10^-17 Joules

The negative sign indicates that work is done on the electron to move it against the electric field.

Question

Sure, here's how you can calculate the work done in accelerating an electron through a potential difference of 220 V:

Step 1: Understand the formula
The work done on a charge q moving through a potential difference V is given by the formula W = qV.

Step 2: Identify the known values
In this case, the charge of an electron (q) is known to be -1.6 x 10^-19 Coulombs and the potential difference (V) is given as 220 V.

Step 3: Substitute the known values into the formula
W = (-1.6 x 10^-19 C) * (220 V)

Step 4: Calculate the result
W = -3.52 x 10^-17 Joules

The negative sign indicates that work is done on the electron to move it against the electric field.

Knowee AI · Accepted Answer

Sure, here's how you can calculate the work done in accelerating an electron through a potential difference of 220 V:

Step 1: Understand the formula
The work done on a charge q moving through a potential difference V is given by the formula W = qV.

Step 2: Identify the known values
In this case, the charge of an electron (q) is known to be -1.6 x 10^-19 Coulombs and the potential difference (V) is given as 220 V.

Step 3: Substitute the known values into the formula
W = (-1.6 x 10^-19 C) * (220 V)

Step 4: Calculate the result
W = -3.52 x 10^-17 Joules

The negative sign indicates that work is done on the electron to move it against the electric field.

Calculate the work done in accelerating an electron through a potential difference of 220 V.

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