The given expression is tancos^(-1)w + 4w^2.

To rewrite this as an algebraic expression in w, we need to understand that cos^(-1)w is the inverse cosine of w, often written as arccos(w).

The tangent of an angle is the ratio of the sine to the cosine of that angle. So, tan(arccos(w)) can be expressed using a Pythagorean identity as sqrt(1 - w^2) / w.

Therefore, the given expression can be rewritten as sqrt(1 - w^2) / w + 4w^2.

Question

The given expression is tancos^(-1)w + 4w^2.

To rewrite this as an algebraic expression in w, we need to understand that cos^(-1)w is the inverse cosine of w, often written as arccos(w).

The tangent of an angle is the ratio of the sine to the cosine of that angle. So, tan(arccos(w)) can be expressed using a Pythagorean identity as sqrt(1 - w^2) / w.

Therefore, the given expression can be rewritten as sqrt(1 - w^2) / w + 4w^2.

Knowee AI · Accepted Answer

The given expression is tancos^(-1)w + 4w^2.

To rewrite this as an algebraic expression in w, we need to understand that cos^(-1)w is the inverse cosine of w, often written as arccos(w).

The tangent of an angle is the ratio of the sine to the cosine of that angle. So, tan(arccos(w)) can be expressed using a Pythagorean identity as sqrt(1 - w^2) / w.

Therefore, the given expression can be rewritten as sqrt(1 - w^2) / w + 4w^2.

Rewrite tancos−1w+4w2 as an algebraic expression in w.

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