A black body has a temperature of 2900 K. The wavelength corresponding to maximum intensity is found to be (in microns) (Wien’s displacement constant = 0.0029 mK)
Question
A black body has a temperature of 2900 K. The wavelength corresponding to maximum intensity is found to be (in microns) (Wien’s displacement constant = 0.0029 mK)
Solution
To find the wavelength corresponding to maximum intensity for a black body, we can use Wien's Displacement Law. The formula for this law is:
λ_max * T = b
where:
- λ_max is the wavelength at which the intensity of radiation is maximum,
- T is the absolute temperature of the black body, and
- b is Wien's displacement constant.
Given in the problem, T = 2900 K and b = 0.0029 mK.
We can rearrange the formula to solve for λ_max:
λ_max = b / T
Substituting the given values:
λ_max = 0.0029 mK / 2900 K
Note that K (Kelvin) in the numerator and denominator will cancel out.
So,
λ_max = 0.0029 / 2900 = 0.000001 m
Since the question asks for the answer in microns, and 1 m = 1,000,000 microns, we convert the answer to microns:
λ_max = 0.000001 m * 1,000,000 µm/m = 1 µm
So, the wavelength corresponding to maximum intensity for a black body at 2900 K is 1 µm.
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