A spherical body of area A and emissivity e=0.6 is kept inside a perfectly black body. Energy radiated per second by the body at temperature T is
Question
A spherical body of area A and emissivity e=0.6 is kept inside a perfectly black body. Energy radiated per second by the body at temperature T is
Solution
The energy radiated per second by a body is given by the Stefan-Boltzmann law, which states that the total energy radiated per unit surface area of a black body in unit time (also known as the black-body radiant emittance) is directly proportional to the fourth power of the black body's thermodynamic temperature T.
The formula is given by:
E = eσAT^4
where:
- E is the energy radiated per second,
- e is the emissivity of the body (which is 0.6 in this case),
- σ is the Stefan-Boltzmann constant (approximately 5.67 x 10^-8 W m^-2 K^-4),
- A is the surface area of the body, and
- T is the temperature of the body.
So, you just need to plug the values of e, σ, A, and T into this formula to get the energy radiated per second by the body.
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