certain vinegar contains an acetic acid with a volume of 55 mL and water with 215 mL. What is the % by volume for the solvent?a.26%b.20%c.80%d.89%

chemist is using 334 milliliters of a solution of acid and water. If 18.7% of the solution is acid, how many milliliters of acid are there? Round your answer to the nearest tenth.milliliters

A solution contains 2.5 cm3 of alcohol mixed with 75 cm3 of water. Calculate the concentration of this solution by volume

A chemist is using 371 milliliters of a solution of acid and water. If 19.3% of the solution is acid, how many milliliters of acid are there? Round your answer to the nearest tenth.

A chemist prepares a mixture of acetone and water at a temperature of 18.0 °C. He measures out 40.1 mL of acetone and mixes it with 303. mL of water. He measures the volume of the solution after it is well mixed and finds that it is 329. mL. The density of acetone is 0.78 /gmL and the density of water is 1.0 /gmL.Calculate the volume percent of acetone in this solution.Be sure your answer has the right number of significant digits.

On domestic products such as vinegar, the concentration of active ingredients is rarely reported in Molar units.  It is more common to report the concentration as a composition such as mass per 100 mL or volume per 100 mL.  Vinegar is usually reported as a volume composition (volume of acetic acid per 100 mL vinegar - written as % v/v).  To convert a molar concentration to % v/v:Calculate how many moles of acetic acid is in 100 mL of solution (Hint: n = C x v)Calculate the mass of acetic acid from the amount of moles determined in step 1 (Hint: m= MW x n)Calculate the volume that the mass determined in step 2 would occupy.  To do this, you will have to divide the mass (determined in step 2) by the density of acetic acid (1.049 g.mL⁻¹).  The density states how much 1 mL of a liquid sample weighs - for acetic acid, 1 mL weighs 1.049 g.The answer in step 3 states what volume of acetic acid is present in a 100 mL sample of vinegar which equates to the composition we are after.  So we can just add "% v/v" to the end of our value to denote this is the volume of acetic acid per 100 mL of vinegar. If, from titration, you determined that concentration of acetic acid in vinegar is 0.928 M, what is the composition of acetic acid in vinegar (% v/v).  Answer to 3 significant figures (please enter numeric value only)