The problem states that x varies directly as the square of y. This can be written as x = ky^2, where k is the constant of variation.

First, we need to find the value of k. We know that when y = 12, x = 4. So we can substitute these values into the equation to find k:

4 = k(12^2)
4 = k(144)
k = 4/144
k = 1/36

Now that we have the value of k, we can find x when y = 18. We substitute these values into the equation:

x = (1/36)(18^2)
x = (1/36)(324)
x = 9

So, the answer is 9.

Question

The problem states that x varies directly as the square of y. This can be written as x = ky^2, where k is the constant of variation.

First, we need to find the value of k. We know that when y = 12, x = 4. So we can substitute these values into the equation to find k:

4 = k(12^2)
4 = k(144)
k = 4/144
k = 1/36

Now that we have the value of k, we can find x when y = 18. We substitute these values into the equation:

x = (1/36)(18^2)
x = (1/36)(324)
x = 9

So, the answer is 9.

Knowee AI · Accepted Answer

The problem states that x varies directly as the square of y. This can be written as x = ky^2, where k is the constant of variation.

First, we need to find the value of k. We know that when y = 12, x = 4. So we can substitute these values into the equation to find k:

4 = k(12^2)
4 = k(144)
k = 4/144
k = 1/36

Now that we have the value of k, we can find x when y = 18. We substitute these values into the equation:

x = (1/36)(18^2)
x = (1/36)(324)
x = 9

So, the answer is 9.

x varies directly as square of y and y =12, x=4. Find x when y =18.a.9/16b.1/9c.16/9d.9