If y varies directly with the square of x and y = 4.3 when x = 5, what is the value of y when x = 6?

Step 1: Understand the problem. The problem states that y varies directly with the square of x. This means that y = kx^2, where k is the constant of variation.

Step 2: Find the constant of variation. We know that y = 4.3 when x = 5. So, we can substitute these values into the equation to find k:

4.3 = k * 5^2 4.3 = k * 25 k = 4.3 / 25 k = 0.172

Step 3: Use the constant of variation to find y when x = 6. Substitute x = 6 and k = 0.172 into the equation:

y = 0.172 * 6^2 y = 0.172 * 36 y = 6.192

So, when x = 6, y = 6.192.