The ratio of the present ages of Mahesh and Ajay is respectively 3: 2. After 8 years, ratio of their ages will be 11: 8. What will be the present age of Mahesh's son if his age is half of the present age of Ajay?
Question
The ratio of the present ages of Mahesh and Ajay is respectively 3: 2. After 8 years, ratio of their ages will be 11: 8. What will be the present age of Mahesh's son if his age is half of the present age of Ajay?
Solution
Let's solve this step by step:
Step 1: Let's assume the present age of Mahesh is 3x and the present age of Ajay is 2x.
Step 2: According to the problem, after 8 years, the ratio of their ages will be 11:8. So, we can write it as (3x+8)/(2x+8) = 11/8.
Step 3: Solving this equation, we get x = 4.
Step 4: So, the present age of Mahesh is 3x = 34 = 12 years and the present age of Ajay is 2x = 24 = 8 years.
Step 5: According to the problem, the present age of Mahesh's son is half of the present age of Ajay. So, the present age of Mahesh's son is 8/2 = 4 years.
So, the present age of Mahesh's son is 4 years.
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