For the following code:fs=12e3;Ts=1/fs;tlen=4.5;t=0:Ts:tlen − Ts;fmin=0.1e3;fmax=3e3;fstep=(fmax − fmin)/length(t);f=fmin:fstep:fmax − fstep;x=sin(2*pi*f.*t);sound(x,fs)plot(t,x)xlabel('time, s')ylabel('amplitude, arbitary units')axis([0 1/fmin*5 − 1 1])How much time will the signal take to play back?
Question
For the following code:fs=12e3;Ts=1/fs;tlen=4.5;t=0:Ts:tlen − Ts;fmin=0.1e3;fmax=3e3;fstep=(fmax − fmin)/length(t);f=fmin:fstep:fmax − fstep;x=sin(2pif.t);sound(x,fs)plot(t,x)xlabel('time, s')ylabel('amplitude, arbitary units')axis([0 1/fmin5 − 1 1])How much time will the signal take to play back?
Solution
The signal will take 4.5 seconds to play back. This is determined by the variable 'tlen' in the code, which is set to 4.5. This variable represents the total length of the signal in seconds.
Similar Questions
or the following code:fs=18.28e3;Ts=1/fs;tlen=4.2;t=0:Ts:tlen − Ts;fmin=0.1e3;fmax=3e3;fstep=(fmax − fmin)/length(t);f=fmin:fstep:fmax − fstep;x=sin(2*pi*f.*t);sound(x,fs)plot(t,x)xlabel('time, s')ylabel('amplitude, arbitary units')axis([0 1/fmin*5 − 1 1])
For the following:f=.5e3;fs=44.1e3;Ts=1/fs;tlen=.5;t=0:Ts:tlen − Ts;x=sin(2*pi*f*t);sound(x,fs)plot(t,x)xlabel('time, s')ylabel('amplitude, arbitary units')axis([0 1/f*10 − 1 1])What is fs?
For the following, drag and drop the statements to the correct lines: Blank 1 Question 2 Blank 2 Question 2f=.5e3;tlen=.5; Blank 3 Question 2 Blank 4 Question 2sound(x,fs) Blank 5 Question 2xlabel('time, s')ylabel('amplitude, arbitary units')axis([0 1/f*10 − 1 1])x=sin(2*pi*f*t); t=0:Ts:tlen − Ts; Ts=1/fs; fs=44.1e3; plot(t,x)
For the following: f1=1.7e3; fs=38e3; Ts=1/fs; tlen=.4; t=0:Ts:tlen-Ts; N=length(t); x=sin(2*pi*f1*t); standev=1; noise=randn(1,N)*standev; xn=x+noise; fcf=720; Omegacf=2*pi*fcf/fs; fo=f1; Omegao=2*pi*fo/fs; M=1001; n=(0:M-1)-floor(M/2); h=Omegacf/pi*sinc(n*Omegacf/pi); w=hamming(M)'; A=1; B=h.*w.*cos(n*Omegao); y=filter(B,A,xn); subplot(2,1,1) plot(t,x,'LineWidth',3); hold on plot(t,xn,'LineWidth',1); plot(t,y,'g','LineWidth',2); axis([1/f1*100 1/f1*110 -4 4]); xlabel('time,s'); ylabel('amplitude, arbitrary units'); legend('original signal','with noise','filtered'); hold off X=fft(x); Xn=fft(xn); Y=fft(y); subplot(2,1,2) fbin=fs/N; f=0:fbin:fs-fbin; plot(f,20*log10(abs(X)),'LineWidth',3); hold on plot(f,20*log10(abs(Xn)),'LineWidth',1); plot(f,20*log10(abs(Y)),'g','LineWidth',2); xlabel('frequency, Hz'); ylabel('magnitude response, dB'); legend('noisy signal spectrum','filtered spectrum') axis([1e2 fs/2 -40 100]) hold off What band of frequencies will this filter keep? Minimum frequency = Answer field 1 kHz. Maximum frequency = Answer field 2 kHz.
What is the frequency of the function y = sec5x?
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