or the following code:fs=18.28e3;Ts=1/fs;tlen=4.2;t=0:Ts:tlen − Ts;fmin=0.1e3;fmax=3e3;fstep=(fmax − fmin)/length(t);f=fmin:fstep:fmax − fstep;x=sin(2*pi*f.*t);sound(x,fs)plot(t,x)xlabel('time, s')ylabel('amplitude, arbitary units')axis([0 1/fmin*5 − 1 1])
Question
or the following code:fs=18.28e3;Ts=1/fs;tlen=4.2;t=0:Ts:tlen − Ts;fmin=0.1e3;fmax=3e3;fstep=(fmax − fmin)/length(t);f=fmin:fstep:fmax − fstep;x=sin(2pif.t);sound(x,fs)plot(t,x)xlabel('time, s')ylabel('amplitude, arbitary units')axis([0 1/fmin5 − 1 1])
Solution 1
The code you provided is written in MATLAB, a high-level language and interactive environment used for numerical computation, visualization, and programming. Here's a step-by-step explanation of what the code does:
-
fs=18.28e3;: This line sets the sampling frequencyfsto 18.28 kHz. This is the rate at which the signal will be sampled. -
Ts=1/fs;: This line calculates the sampling periodTs, which is the reciprocal of the sampling frequency. -
tlen=4.2;: This line sets the length of the time vectortlento 4.2 seconds. -
t=0:Ts:tlen − Ts;: This line creates a time vectortthat starts at 0, increments byTs, and ends attlen - Ts. -
fmin=0.1e3;fmax=3e3;: These lines set the minimum frequencyfminto 0.1 kHz and the maximum frequencyfmaxto 3 kHz. -
fstep=(fmax − fmin)/length(t);: This line calculates the frequency stepfstep. -
f=fmin:fstep:fmax − fstep;: This line creates a frequency vectorfthat starts atfmin, increments byfstep, and ends atfmax - fstep. -
x=sin(2*pi*f.*t);: This line generates a sinusoidal signalxwith the frequencyfand timet. -
sound(x,fs): This line plays the sound of the signalxat the sampling frequencyfs. -
plot(t,x): This line plots the signalxagainst the time vectort. -
xlabel('time, s')ylabel('amplitude, arbitary units'): These lines label the x-axis as 'time, s' and the y-axis as 'amplitude, arbitrary units'. -
axis([0 1/fmin*5 − 1 1]): This line sets the limits of the x-axis and y-axis for the plot.
Please note that the code you provided seems to have some syntax errors. The correct code should look like this:
fs=18.28e3;
Ts=1/fs;
tlen=4.2;
t=0:Ts:tlen-Ts;
fmin=0.1e3;
fmax=3e3;
fstep=(fmax-fmin)/length(t);
f=fmin:fstep:fmax-fstep;
x=sin(2*pi*f.*t);
sound(x,fs)
plot(t,x)
xlabel('time, s')
ylabel('amplitude, arbitrary units')
axis([0 1/fmin*5 -1 1])
Solution 2
The code you provided is written in MATLAB, a high-level language and interactive environment used for numerical computation, visualization, and programming. Here's a step-by-step explanation of what the code does:
-
fs=18.28e3;: This line sets the sampling frequencyfsto 18.28 kHz. This is the rate at which the signal will be sampled. -
Ts=1/fs;: This line calculates the sampling periodTs, which is the reciprocal of the sampling frequency. -
tlen=4.2;: This line sets the length of the time vectortlento 4.2 seconds. -
t=0:Ts:tlen − Ts;: This line creates a time vectortthat starts at 0, increments byTs, and ends attlen - Ts. -
fmin=0.1e3;fmax=3e3;: These lines set the minimum frequencyfminto 0.1 kHz and the maximum frequencyfmaxto 3 kHz. -
fstep=(fmax − fmin)/length(t);: This line calculates the frequency stepfstep. -
f=fmin:fstep:fmax − fstep;: This line creates a frequency vectorfthat starts atfmin, increments byfstep, and ends atfmax - fstep. -
x=sin(2*pi*f.*t);: This line generates a sinusoidal signalxwith the frequencyfand timet. -
sound(x,fs): This line plays the sound of the signalxat the sampling frequencyfs. -
plot(t,x): This line plots the signalxagainst the time vectort. -
xlabel('time, s')ylabel('amplitude, arbitary units'): These lines label the x-axis as 'time, s' and the y-axis as 'amplitude, arbitrary units'. -
axis([0 1/fmin*5 − 1 1]): This line sets the limits of the x-axis and y-axis for the plot.
Please note that the code you provided seems to have some syntax errors. The correct code should look like this:
fs=18.28e3;
Ts=1/fs;
tlen=4.2;
t=0:Ts:tlen-Ts;
fmin=0.1e3;
fmax=3e3;
fstep=(fmax-fmin)/length(t);
f=fmin:fstep:fmax-fstep;
x=sin(2*pi*f.*t);
sound(x,fs)
plot(t,x)
xlabel('time, s')
ylabel('amplitude, arbitrary units')
axis([0 1/fmin*5 -1 1])
Similar Questions
For the following code:fs=12e3;Ts=1/fs;tlen=4.5;t=0:Ts:tlen − Ts;fmin=0.1e3;fmax=3e3;fstep=(fmax − fmin)/length(t);f=fmin:fstep:fmax − fstep;x=sin(2*pi*f.*t);sound(x,fs)plot(t,x)xlabel('time, s')ylabel('amplitude, arbitary units')axis([0 1/fmin*5 − 1 1])How much time will the signal take to play back?
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For the following, drag and drop the statements to the correct lines: Blank 1 Question 1 Blank 2 Question 1f=.5e3;tlen=.5; Blank 3 Question 1 Blank 4 Question 1sound(x,fs) Blank 5 Question 1xlabel('time, s')ylabel('amplitude, arbitary units')axis([0 1/f*10 − 1 1])t=0:Ts:tlen − Ts; Ts=1/fs; x=sin(2*pi*f*t); fs=44.1e3; plot(t,x)
The time period of a sound wave is 0.020 s. What is its frequency?
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