he electromagnetic wave travels in a medium at a speed of 2.0 × 108m/s. The relative permeability of the medium is 1.0. The relative permittivity of the medium will be:

he refractive index and permeability of a medium are 1.51.5 and 5×10−7 H m−15×10-7 H m-1 respectively. The relative permittivity of the medium is nearly

Given the following medium parameters εr  = 1, σ = 0, μr  = 1Find the speed of electromagnetic wave.

A plane electromagnetic wave travels in a medium of relative permeability 1.6 and relative permittivity 6.44. If magnitude of magnetic intensity is 4.5 × 10–2 A m–1 at a point, what will be the approximate magnitude of electric field intensity at that point? (Given: permeability of free space  μ0  =  4π × 10−7​N​A−2, speed of light in vacuum c = 3 × 108 m/s)

If ε0 and μ0 are the electric permittivity and magnetic permeability in vacuum, ε and μ are corresponding quantities in medium, then refractive index of the medium isεε0−−√ε0μεμ0−−−√ε0μ0εμ−−−√εμε0μ0−−−√

For a plane travelling EM wave. the correct equation for characteristic impedance Z for the medium with permittivity of ε and permeability of µ isa) Z = b) Z = c) Z = d) Z = 1 /