As per typical I-V Characteristic of ultrafast diode: MUR1660CTG, the Dynamic resistance at 25 degrees Celsius is approximately:0.125 Ohms and the Max. instantaneous forward voltage is 1.5 V. If a square wave current of 10A peak and 50 percent duty cycle is passed through the diode. The total conduction loss in the diode in Watts would be:
Question
As per typical I-V Characteristic of ultrafast diode: MUR1660CTG, the Dynamic resistance at 25 degrees Celsius is approximately:0.125 Ohms and the Max. instantaneous forward voltage is 1.5 V. If a square wave current of 10A peak and 50 percent duty cycle is passed through the diode. The total conduction loss in the diode in Watts would be:
Solution
The conduction loss in a diode can be calculated using the formula:
P = I^2 * R
where: P is the power loss, I is the current, and R is the resistance.
However, since the current is a square wave with a 50% duty cycle, the effective current (I_eff) is given by:
I_eff = I_peak * sqrt(D)
where: I_peak is the peak current, and D is the duty cycle.
Substituting the given values:
I_eff = 10A * sqrt(0.5) = 7.07A
Substituting I_eff into the power loss formula:
P = (7.07A)^2 * 0.125 Ohms = 6.25W
Therefore, the total conduction loss in the diode is approximately 6.25 Watts.
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