A random assortment of tiles with letters on them are placed into a bag. There are 1818 tiles in total. One tile is drawn out of the bag. There is a 1991 probability of that tile being a "T". How many "T"s are there in the bag?
Question
A random assortment of tiles with letters on them are placed into a bag. There are 1818 tiles in total. One tile is drawn out of the bag. There is a 1991 probability of that tile being a "T". How many "T"s are there in the bag?
Solution
To find out how many "T" tiles are in the bag, we need to use the given probability and the total number of tiles.
The probability of drawing a "T" tile is given as 1991. This is likely a typo, as probabilities are typically expressed as a fraction or decimal between 0 and 1. Assuming the probability was meant to be 19/91, we can proceed with the calculation.
Step 1: Understand the probability The probability of an event is calculated as the number of ways that event can occur divided by the total number of outcomes. In this case, the event is drawing a "T" tile, and the total number of outcomes is the total number of tiles, which is 1818.
Step 2: Set up the equation We can set up the equation as follows: (Number of "T" tiles / Total number of tiles) = Probability of drawing a "T" tile Let's denote the number of "T" tiles as T. So the equation becomes: (T / 1818) = 19/91
Step 3: Solve the equation To solve for T, we can cross-multiply: T = (19/91) * 1818
Step 4: Calculate the result When you do the calculation, you get T ≈ 380.
So, there are approximately 380 "T" tiles in the bag.
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