To solve this problem, we need to calculate the probability of drawing two tiles of the same letter one after the other without replacement.

There are 6 tiles in total, 3 of them are "T", and 2 of them are "O".

First, let's calculate the probability of drawing a "T" twice in a row. The probability of drawing a "T" on the first draw is 3/6 or 1/2. After drawing one "T", there are only 2 "T"s left and 5 tiles in total. So, the probability of drawing a "T" on the second draw is 2/5.

The probability of both events happening is (1/2) * (2/5) = 1/5 or 0.2.

Next, let's calculate the probability of drawing an "O" twice in a row. The probability of drawing an "O" on the first draw is 2/6 or 1/3. After drawing one "O", there is only 1 "O" left and 5 tiles in total. So, the probability of drawing an "O" on the second draw is 1/5.

The probability of both events happening is (1/3) * (1/5) = 1/15 or approximately 0.067.

To find the total probability of drawing two tiles of the same letter one after another, we add the probabilities we calculated: 0.2 + 0.067 = 0.267 or approximately 4/15.

So, the correct answer is D4/15.

Question

To solve this problem, we need to calculate the probability of drawing two tiles of the same letter one after the other without replacement.

There are 6 tiles in total, 3 of them are "T", and 2 of them are "O".

First, let's calculate the probability of drawing a "T" twice in a row. The probability of drawing a "T" on the first draw is 3/6 or 1/2. After drawing one "T", there are only 2 "T"s left and 5 tiles in total. So, the probability of drawing a "T" on the second draw is 2/5.

The probability of both events happening is (1/2) * (2/5) = 1/5 or 0.2.

Next, let's calculate the probability of drawing an "O" twice in a row. The probability of drawing an "O" on the first draw is 2/6 or 1/3. After drawing one "O", there is only 1 "O" left and 5 tiles in total. So, the probability of drawing an "O" on the second draw is 1/5.

The probability of both events happening is (1/3) * (1/5) = 1/15 or approximately 0.067.

To find the total probability of drawing two tiles of the same letter one after another, we add the probabilities we calculated: 0.2 + 0.067 = 0.267 or approximately 4/15.

So, the correct answer is D4/15.

Knowee AI · Accepted Answer

To solve this problem, we need to calculate the probability of drawing two tiles of the same letter one after the other without replacement.

There are 6 tiles in total, 3 of them are "T", and 2 of them are "O".

First, let's calculate the probability of drawing a "T" twice in a row. The probability of drawing a "T" on the first draw is 3/6 or 1/2. After drawing one "T", there are only 2 "T"s left and 5 tiles in total. So, the probability of drawing a "T" on the second draw is 2/5.

The probability of both events happening is (1/2) * (2/5) = 1/5 or 0.2.

Next, let's calculate the probability of drawing an "O" twice in a row. The probability of drawing an "O" on the first draw is 2/6 or 1/3. After drawing one "O", there is only 1 "O" left and 5 tiles in total. So, the probability of drawing an "O" on the second draw is 1/5.

The probability of both events happening is (1/3) * (1/5) = 1/15 or approximately 0.067.

To find the total probability of drawing two tiles of the same letter one after another, we add the probabilities we calculated: 0.2 + 0.067 = 0.267 or approximately 4/15.

So, the correct answer is D4/15.

In a bag of a few scrabble tiles, there are the letters “T”, “T”, “T”, “O”, “O”, “E”. The probability of drawing two tiles of the same letter one after another without replacement is…A8/15B1/3C1/90D4/15

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