KNUST also known as MIT of Africa has some students who are supposed to perform an experiment with a semi conductor device. Engineer Commey desires to obtain same hole and electron drift current. How is carrier concentrations supposed to be chosen
Question
KNUST also known as MIT of Africa has some students who are supposed to perform an experiment with a semi conductor device. Engineer Commey desires to obtain same hole and electron drift current. How is carrier concentrations supposed to be chosen
Solution
In a semiconductor device, the drift current due to holes and electrons can be made equal by choosing the carrier concentrations appropriately. Here's how:
-
Understand the Drift Current: The drift current is the current due to the movement of charge carriers (electrons and holes) under the influence of an electric field. It's given by the formula: J = qnμE, where J is the current density, q is the charge of the carrier, n is the number of carriers per unit volume (carrier concentration), μ is the mobility of the carrier, and E is the electric field.
-
Equalize Electron and Hole Currents: To have the same hole and electron drift current, the product of the carrier concentration and mobility must be the same for both types of carriers. That is, n_eμ_e = n_hμ_h, where the subscripts e and h refer to electrons and holes respectively.
-
Choose Carrier Concentrations: Given the mobilities of the electrons and holes (which are properties of the material and temperature), you can solve the above equation for the required carrier concentration. For example, if the electron mobility is higher than the hole mobility, you would need a higher hole concentration to equalize the currents.
-
Implement in Practice: In practice, adjusting carrier concentrations can be achieved through a process called doping, where impurities are added to the semiconductor to increase the number of either free electrons (n-type doping) or holes (p-type doping).
Remember, this is a simplified explanation. The actual process involves complex physics and precise control over material properties.
Similar Questions
The carrier concentration in a material of conductivity 0.018/ohm m is 1019 electrons/m3. A voltage of 0.16 volts is applied across the 0.29 mm thick material. Determine the driftvelocity of the carriers. Take standard values of mass of electron and electronic charge.
The drift velocity of electrons for a conductor connected in an electrical circuit is Vd. The conductor in now replaced by another conductor with same material and same length but double the area of cross section. The applied voltage remains same. The new drift velocity of electrons will be
Which of the experiment directly determines both the sign and density of charge carriers in a sample material is.Question 2AnswerA.Four-Probe methodB.Band-Gap determinationC.Current-Voltage CharacteristicsD.Hall-Effect experiment
Consider a conductor of length 0.5 m. A potential difference of 20V is applied across this conductor. If the drift velocity of electrons is given as 5.0 × 10-4ms-1, then determine the mobility of the electrons.
An aluminum wire having a cross-sectional area equal to 2.20 10-6 m2 carries a current of 5.50 A. The density of aluminum is 2.70 g/cm3. Assume each aluminum atom supplies one conduction electron per atom. Find the drift speed of the electrons in the wire. The equation for the drift velocity includes the number of charge carriers per volume, which in this case is equal to the number of atoms per volume. How do you calculate that if you know the density and the atomic weight of aluminum? mm
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.