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2.0 A in the 100-turn primary of a transformer causes 14 A to flow in the secondary. How many turns are in the secondary?Group of answer choices700144114

Question

2.0 A in the 100-turn primary of a transformer causes 14 A to flow in the secondary. How many turns are in the secondary?Group of answer choices700144114

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Solution

Para resolver este problema, utilizamos la relación de transformación de un transformador, que se basa en la ley de Faraday y la conservación de la energía. La relación de transformación se puede expresar como:

NpNs=IsIp \frac{N_p}{N_s} = \frac{I_s}{I_p}

donde:

  • Np N_p es el número de vueltas en el primario.
  • Ns N_s es el número de vueltas en el secundario.
  • Ip I_p es la corriente en el primario.
  • Is I_s es la corriente en el secundario.

Dado:

  • Np=100 N_p = 100 vueltas
  • Ip=2.0 I_p = 2.0 A
  • Is=14 I_s = 14 A

Sustituimos estos valores en la fórmula:

100Ns=142.0 \frac{100}{N_s} = \frac{14}{2.0}

Simplificamos la fracción en el lado derecho:

100Ns=7 \frac{100}{N_s} = 7

Para encontrar Ns N_s , despejamos Ns N_s :

Ns=1007 N_s = \frac{100}{7}

Calculamos el valor:

Ns≈14.29 N_s \approx 14.29

Dado que el número de vueltas debe ser un número entero, redondeamos al valor más cercano, que es 14.

Por lo tanto, el número de vueltas en el secundario es 14.

This problem has been solved

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