A room measuring 6m 65 cm long and 4 m 55 cm broad is to be paved with the least number of squared tiles. Then the least number of squared tiles required to cover the floor is

To solve this problem, we first need to convert the measurements of the room into the same units. In this case, we'll convert everything into centimeters:

• The length of the room is 6 meters 65 centimeters, which is equal to 665 centimeters.
• The breadth of the room is 4 meters 55 centimeters, which is equal to 455 centimeters.

Next, we need to find the greatest common divisor (GCD) of the length and the breadth. The GCD represents the largest size of the square tile that can be used to pave the room without leaving any gaps or needing to cut any tiles.

The GCD of 665 and 455 is 5.

So, the size of each tile will be 5cm x 5cm.

Finally, we need to calculate the total number of tiles required. This is done by dividing the total area of the room by the area of each tile:

• The total area of the room is 665cm x 455cm = 302575 square cm.
• The area of each tile is 5cm x 5cm = 25 square cm.

So, the total number of tiles required is 302575 / 25 = 12103.

Therefore, the least number of square tiles required to cover the floor is 12103.