What is the output of the following C program ?void main (){const int x = 5;const int *ptrx;ptrx = &x;*ptrx = 10;printf("%d", x);}A5BCompilation ErrorC10DGarbage ValuePrevious
Question
What is the output of the following C program ?void main (){const int x = 5;const int *ptrx;ptrx = &x;*ptrx = 10;printf("%d", x);}A5BCompilation ErrorC10DGarbage ValuePrevious
Solution
The output of the given C program would be a Compilation Error.
Here's why:
In the C programming language, the keyword 'const' is used to make a variable constant, meaning its value cannot be changed after it has been declared and initialized.
In the given program, 'x' is declared as a constant integer and initialized with the value 5. Then a pointer 'ptrx' is declared as a pointer to a constant integer. The address of 'x' is assigned to 'ptrx', which is perfectly fine.
However, the next line attempts to change the value of 'x' through the pointer 'ptrx' by dereferencing the pointer. This is not allowed because 'x' is a constant.
Therefore, the compiler will throw an error at the line '*ptrx = 10;', and the program will not run. Hence, the correct answer is B: Compilation Error.
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