The question seems to be incomplete, as it doesn't specify what we need to find out about the sphere. However, it seems like it might be asking for the rate at which the sphere is losing heat to its environment, which can be calculated using the Stefan-Boltzmann Law.

Here's how you would do it:

1. First, we need to convert the temperatures from Celsius to Kelvin, because the Stefan-Boltzmann Law requires temperatures to be in Kelvin. To do this, we add 273.15 to each temperature. So, 297.0 °C becomes 570.15 K and 16.5 °C becomes 289.65 K.

2. Next, we calculate the surface area of the sphere using the formula 4πr², where r is the radius of the sphere. In this case, the radius is 59.1 cm, but we need to convert it to meters by dividing by 100, so r = 0.591 m. Plugging

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The question seems to be incomplete, as it doesn't specify what we need to find out about the sphere. However, it seems like it might be asking for the rate at which the sphere is losing heat to its environment, which can be calculated using the Stefan-Boltzmann Law.

Here's how you would do it:

1. First, we need to convert the temperatures from Celsius to Kelvin, because the Stefan-Boltzmann Law requires temperatures to be in Kelvin. To do this, we add 273.15 to each temperature. So, 297.0 °C becomes 570.15 K and 16.5 °C becomes 289.65 K.

2. Next, we calculate the surface area of the sphere using the formula 4πr², where r is the radius of the sphere. In this case, the radius is 59.1 cm, but we need to convert it to meters by dividing by 100, so r = 0.591 m. Plugging

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The question seems to be incomplete, as it doesn't specify what we need to find out about the sphere. However, it seems like it might be asking for the rate at which the sphere is losing heat to its environment, which can be calculated using the Stefan-Boltzmann Law.

Here's how you would do it:

1. First, we need to convert the temperatures from Celsius to Kelvin, because the Stefan-Boltzmann Law requires temperatures to be in Kelvin. To do this, we add 273.15 to each temperature. So, 297.0 °C becomes 570.15 K and 16.5 °C becomes 289.65 K.

2. Next, we calculate the surface area of the sphere using the formula 4πr², where r is the radius of the sphere. In this case, the radius is 59.1 cm, but we need to convert it to meters by dividing by 100, so r = 0.591 m. Plugging

A sphere of metal with emissivity 0.8360.836 is at temperature 297.0 ∘C297.0 ∘C in an environment with 16.5 ∘C.16.5 ∘C. The sphere has a radius 59.1 cm.59.1 cm..

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