A well collimated parallel pencil of cathode rays fallsthrough a potential difference 3 kV & enters the spacing betweentwo parallel metallic plates, parallel to their length the spacingbetween the plates being 0.5 cm. The pencil strikes a fluorescentscreen, mounted perpendicular to the length of the plates at thefarther end of the plates & produces fluorescent spot. If now apotential difference of 3V is applied across the two plates,calculate the linear deflection of the spot on the screen. Giventhe length of the plates is 10 cm.
Question
A well collimated parallel pencil of cathode rays fallsthrough a potential difference 3 kV & enters the spacing betweentwo parallel metallic plates, parallel to their length the spacingbetween the plates being 0.5 cm. The pencil strikes a fluorescentscreen, mounted perpendicular to the length of the plates at thefarther end of the plates & produces fluorescent spot. If now apotential difference of 3V is applied across the two plates,calculate the linear deflection of the spot on the screen. Giventhe length of the plates is 10 cm.
Solution
Given:
- Potential difference across the plates: 3 kV
- Spacing between the plates: 0.5 cm
- Length of the plates: 10 cm
- Potential difference applied across the plates: 3V
To calculate the linear deflection of the spot on the screen, we can use the formula for the deflection of charged particles in an electric field.
Step 1: Calculate the electric field between the plates. The electric field (E) can be calculated using the formula: E = V / d where V is the potential difference and d is the spacing between the plates.
Substituting the given values: E = 3 kV / 0.5 cm
Step 2: Calculate the force on the cathode rays. The force (F) on the cathode rays can be calculated using the formula: F = q * E where q is the charge of the cathode rays and E is the electric field.
Step 3: Calculate the acceleration of the cathode rays. The acceleration (a) of the cathode rays can be calculated using the formula: a = F / m where F is the force on the cathode rays and m is the mass of the cathode rays.
Step 4: Calculate the velocity of the cathode rays. The velocity (v) of the cathode rays can be calculated using the formula: v = u + a * t where u is the initial velocity of the cathode rays, a is the acceleration, and t is the time taken.
Step 5: Calculate the deflection of the spot on the screen. The deflection (d) of the spot on the screen can be calculated using the formula: d = v * t where v is the velocity of the cathode rays and t is the time taken.
By following these steps and substituting the given values, you can calculate the linear deflection of the spot on the screen.
Similar Questions
A well collimated parallel pencil of cathode rays fallsthrough a potential difference 3 kV & enters the spacing betweentwo parallel metallic plates, parallel to their length the spacingbetween the plates being 0.5 cm. The pencil strikes a fluorescentscreen, mounted perpendicular to the length of the plates at thefarther end of the plates & produces fluorescent spot. If now apotential difference of 3V is applied across the two plates,calculate the linear deflection of the spot on the screen. Giventhe length of the plates is 10 cm.
Cathode rays
Cathode rays are made up of
Cathode rays haveA only mass. B only charge. C neither mass nor charge. D both mass and charge.
The diagram below represents a cathode ray tube in which electrons emitted from the hot filament are accelerated towards the positively charged screen. The electric field in the evacuated space between the screen and filament has a constant magnitude of 105 Vm-1. The speed of the electrons on reaching the screen is:Select one:a.8.4x107 ms-1.b.1.8x1016 ms-1.c.2.0x103 ms-1.d.1.0x104 ms-1.e.3.7x106 ms-1.Clear my choice
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