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Solve for the magnitude of the fourth displacement vector ๐น= (6๐ตโˆ’ 2๐ถ+ ๐ด) m, giventhe following displacement vectors:๐ด = (5๐‘–ฬ‚+ 2๐‘—ฬ‚โˆ’ 9๐‘˜ ฬ‚) m๐ต= (8๐‘–ฬ‚+ 3๐‘—ฬ‚+๐‘˜ ฬ‚) m๐ถ = (4๐‘–ฬ‚โˆ’ 7๐‘—ฬ‚โˆ’ 6๐‘˜ ฬ‚) m

Question

Solve for the magnitude of the fourth displacement vector ๐น= (6๐ตโˆ’ 2๐ถ+ ๐ด) m, giventhe following displacement vectors:๐ด = (5๐‘–ฬ‚+ 2๐‘—ฬ‚โˆ’ 9๐‘˜ ฬ‚) m๐ต= (8๐‘–ฬ‚+ 3๐‘—ฬ‚+๐‘˜ ฬ‚) m๐ถ = (4๐‘–ฬ‚โˆ’ 7๐‘—ฬ‚โˆ’ 6๐‘˜ ฬ‚) m

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Solution

To solve for the magnitude of the fourth displacement vector F, we first need to substitute the given vectors A, B, and C into the equation for F.

F = 6B - 2C + A

Substituting the given vectors:

F = 6(8i + 3j + k) - 2(4i - 7j - 6k) + (5i + 2j - 9k)

Simplify the equation by distributing and combining like terms:

F = (48i + 18j + 6k) - (8i - 14j - 12k) + (5i + 2j - 9k)

F = (48 - 8 + 5)i + (18 + 14 + 2)j + (6 - 12 - 9)k

F = 45i + 34j - 15k

The magnitude of a vector F = (a, b, c) is given by the formula โˆš(aยฒ + bยฒ + cยฒ).

So, the magnitude of F is โˆš((45)ยฒ + (34)ยฒ + (-15)ยฒ) = โˆš(2025 + 1156 + 225) = โˆš3406 โ‰ˆ 58.34 m.

This problem has been solved

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