An alloy contains zinc and brass in the ratio 5:3. If 4 g of zinc is added to the mixture, then the ratio becomes 7: 3. What is the quantity of brass in the given alloy?
Question
An alloy contains zinc and brass in the ratio 5:3. If 4 g of zinc is added to the mixture, then the ratio becomes 7: 3. What is the quantity of brass in the given alloy?
Solution
Let's denote the initial quantity of zinc as 5x and the initial quantity of brass as 3x (since the ratio is 5:3).
According to the problem, when 4g of zinc is added, the ratio of zinc to brass becomes 7:3. So, we can write the equation:
(5x + 4) / 3x = 7 / 3
Solving this equation for x gives:
15x + 12 = 21x 6x = 12 x = 2
So, the initial quantity of brass is 3x = 3*2 = 6g.
Therefore, the quantity of brass in the given alloy is 6g.
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