Here is a step-by-step solution to the problem: 1. First, sort the given array in ascending order. This will help in easily moving towards the target sum. 2. Initialize a variable, say `closestSum`, to store the sum of three integers closest to the target. Initially, set it as the sum of the first three elements in the sorted array. 3. Now, start iterating over the array from the first element to the third last element (inclusive). For each element, perform the

Given an integer array nums of length n and an integer target, find three integers in nums such that the sum is closest to target.Return the sum of the three integers.You may assume that each input would have exactly one solution. Example 1:Input: nums = [-1,2,1,-4], target = 1Output: 2Explanation: The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).Example 2:Input: nums = [0,0,0], target = 1Output: 0Explanation: The sum that is closest to the target is 0. (0 + 0 + 0 = 0). Constraints:3 <= nums.length <= 500-1000 <= nums[i] <= 1000-104 <= target <= 104

Question

Given an integer array nums of length n and an integer target, find three integers in nums such that the sum is closest to target.Return the sum of the three integers.You may assume that each input would have exactly one solution. Example 1:Input: nums = [-1,2,1,-4], target = 1Output: 2Explanation: The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).Example 2:Input: nums = [0,0,0], target = 1Output: 0Explanation: The sum that is closest to the target is 0. (0 + 0 + 0 = 0). Constraints:3 <= nums.length <= 500-1000 <= nums[i] <= 1000-104 <= target <= 104

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Solution 1

Here is a step-by-step solution to the problem:

First, sort the given array in ascending order. This will help in easily moving towards the target sum.
Initialize a variable, say closestSum, to store the sum of three integers closest to the target. Initially, set it as the sum of the first three elements in the sorted array.
Now, start iterating over the array from the first element to the third last element (inclusive). For each element, perform the

This problem has been solved

Solution 2

Here is a step-by-step solution to the problem:

First, sort the given array in ascending order. This will help in easily moving towards the target sum.
Initialize a variable, say closestSum, to store the closest sum we can find. Initially, set it to the sum of the first three elements in the sorted array.
Now, start iterating over the array. For each element at index i, perform the following steps:
- Initialize two pointers, left and right. Set left to i+1 and right to the last index of the array.
- While left is less than right, calculate the sum of elements at index i, left, and right. Let's call this currentSum.
- If currentSum is equal to the target, then we have found the closest possible sum. So, return currentSum.
- If currentSum is not equal to target, then check if the absolute difference between currentSum and target is less than the absolute difference between closestSum and target. If it is, then update closestSum to currentSum.
- If currentSum is less than target, then increment left by 1. This is because we need to increase our sum to get closer to the target.

This problem has been solved

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