1.1 Two SumGiven an array of integers nums and an integer target, return indices of the two numbers such that theyadd up to target. You may assume that each input would have exactly one solution, and you may not usethe same element twice. You can return the answer in any order.Input: nums = [2, 7, 11, 15], target = 9Output: [0, 1]Explanation: Because nums[0] + nums[1] == 9, so return [0, 1].Input: nums = [3, 2, 4], target = 6Output: [1, 2]Input: nums = [3, 3], target = 6Output: [0, 1]Hints:def twoSum(self, nums: List[int], target: int) -> List[int]:a=[]# Write code here…return a1.2 Contains DuplicateGiven an integer array nums, return true if any value appears at least twice in the array, and return false ifevery element is distinct.Input: nums = [1, 2, 3, 1]Output: trueInput: nums = [1, 2, 3, 4]Output: falseInput: nums = [1, 1, 1, 3, 3, 4, 3, 2, 4, 2]Output: trueHints:
Question
1.1 Two SumGiven an array of integers nums and an integer target, return indices of the two numbers such that theyadd up to target. You may assume that each input would have exactly one solution, and you may not usethe same element twice. You can return the answer in any order.Input: nums = [2, 7, 11, 15], target = 9Output: [0, 1]Explanation: Because nums[0] + nums[1] == 9, so return [0, 1].Input: nums = [3, 2, 4], target = 6Output: [1, 2]Input: nums = [3, 3], target = 6Output: [0, 1]Hints:def twoSum(self, nums: List[int], target: int) -> List[int]:a=[]# Write code here…return a1.2 Contains DuplicateGiven an integer array nums, return true if any value appears at least twice in the array, and return false ifevery element is distinct.Input: nums = [1, 2, 3, 1]Output: trueInput: nums = [1, 2, 3, 4]Output: falseInput: nums = [1, 1, 1, 3, 3, 4, 3, 2, 4, 2]Output: trueHints:
Solution
Sure, here are the solutions for the problems you provided:
1.1 Two Sum
def twoSum(nums, target):
h = {}
for i, num in enumerate(nums):
n = target - num
if n not in h:
h[num] = i
else:
return [h[n], i]
This function works by creating a dictionary h where for each number in nums, we check if target - num is in the dictionary. If it is, we return the indices of these two numbers. If it's not, we add the number and its index to the dictionary.
1.2 Contains Duplicate
def containsDuplicate(nums):
return len(nums) != len(set(nums))
This function works by converting the list nums to a set, which removes any duplicate values. If the length of the original list and the set are different, it means that there were duplicates in the list, so we return True. If they're the same length, it means there were no duplicates, so we return False.
Similar Questions
Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.You may assume that each input would have exactly one solution, and you may not use the same element twice.
Write a Python class to find a pair of elements (indices of the two numbers) from a given array whose sum equals a specific target number.Note: There will be one solution for each input and do not use the same element twice.Sample Test CasesTest Case 1:Expected Output:Enter·comma-separated·numbers:·2,5,1,5,6,0Enter·target·value:·10index1=1,·index2=3Test Case 2:Expected Output:Enter·comma-separated·numbers:·3,4,5,6,2,9Enter·target·value:·9index1=0,·index2=3Test Case 3:Expected Output:Enter·comma-separated·numbers:·9,8,1,4,5Enter·target·value:·4No·valid·indices·found·for·the·target·value.
Given an integer array nums of length n and an integer target, find three integers in nums such that the sum is closest to target.Return the sum of the three integers.You may assume that each input would have exactly one solution. Example 1:Input: nums = [-1,2,1,-4], target = 1Output: 2Explanation: The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).Example 2:Input: nums = [0,0,0], target = 1Output: 0Explanation: The sum that is closest to the target is 0. (0 + 0 + 0 = 0). Constraints:3 <= nums.length <= 500-1000 <= nums[i] <= 1000-104 <= target <= 104
You are given an integer array nums sorted in non-decreasing order.Build and return an integer array result with the same length as nums such that result[i] is equal to the summation of absolute differences between nums[i] and all the other elements in the array.In other words, result[i] is equal to sum(|nums[i]-nums[j]|) where 0 <= j < nums.length and j != i (0-indexed). Example 1:Input: nums = [2,3,5]Output: [4,3,5]Explanation: Assuming the arrays are 0-indexed, thenresult[0] = |2-2| + |2-3| + |2-5| = 0 + 1 + 3 = 4,result[1] = |3-2| + |3-3| + |3-5| = 1 + 0 + 2 = 3,result[2] = |5-2| + |5-3| + |5-5| = 3 + 2 + 0 = 5.Example 2:Input: nums = [1,4,6,8,10]Output: [24,15,13,15,21]
Given an integer array nums, return true if you can partition the array into two subsets such that the sum of the elements in both subsets is equal or false otherwise. Example 1:Input: nums = [1,5,11,5]Output: trueExplanation: The array can be partitioned as [1, 5, 5] and [11].Example 2:Input: nums = [1,2,3,5]Output: falseExplanation: The array cannot be partitioned into equal sum subsets. Constraints:1 <= nums.length <= 2001 <= nums[i] <= 100
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