Given the array houses where houses[i] is the location of the ith house along a street and an integer k, allocate k mailboxes in the street.Return the minimum total distance between each house and its nearest mailbox.The test cases are generated so that the answer fits in a 32-bit integer.
Question
Given the array houses where houses[i] is the location of the ith house along a street and an integer k, allocate k mailboxes in the street.Return the minimum total distance between each house and its nearest mailbox.The test cases are generated so that the answer fits in a 32-bit integer.
Solution
It seems like you're asking for a solution to a programming problem. Here's a Python solution using dynamic programming:
def minDistance(houses, k):
houses.sort()
n = len(houses)
dp = [[0]*k for _ in range(n)]
cost = [[0]*n for _ in range(n)]
for i in range(n):
for j in range(i+1, n):
Similar Questions
K-ClosenessYou are given an array 𝐴A of length 𝑁N, and an integer 𝐾K.You can perform the following operation:Choose any index 𝑖i (1≤𝑖≤𝑁1≤i≤N), and increase 𝐴𝑖A i by 𝐾K.Find the minimum possible value of max(𝐴)−min(𝐴)max(A)−min(A) attainable, if you can perform this operation as many times as you like (possibly, zero times).Input FormatThe first line of input will contain a single integer 𝑇T, denoting the number of test cases.Each test case consists of two lines of input.The first line of each test case contains two space-separated integers 𝑁N and 𝐾K — the length of the array and the parameter 𝐾K.The second line contains 𝑁N space-separated integers 𝐴1,𝐴2,…,𝐴𝑁A 1 ,A 2 ,…,A N — the initial values of the array elements.Output FormatFor each test case, output on a new line the answer: the minimum possible value of max(𝐴)−min(𝐴)max(A)−min(A) if you can perform the given operation any number of times.Constraints1≤𝑇≤1051≤T≤10 5 1≤𝑁≤2⋅1051≤N≤2⋅10 5 1≤𝐾≤1091≤K≤10 9 1≤𝐴𝑖≤1091≤A i ≤10 9 The sum of 𝑁N over all test cases won't exceed 2⋅1052⋅10 5 .Sample 1:InputOutput43 41 5 43 212 8 44 11 43 62 8256 121 2 4 128 130 1311008Explanation:Test case 11: Increase the first element by 𝐾=4K=4 to obtain the array [5,5,4][5,5,4].Here, max−min=5−4=1max−min=5−4=1, which is the best possible.Test case 22: The second and third elements can be increased by 22 till they reach 1212, at which point all the elements of the array are equal, so max(𝐴)−min(𝐴)=0max(A)−min(A)=0.Test case 33: Since 𝐾=1K=1, again it's possible to make all the elements equal.Test case 44: Do the following:Increase 𝐴1A 1 by 1212 repeatedly to make it 133133.Increase 𝐴2A 2 by 1212 repeatedly to make it 134134.Increase 𝐴3A 3 by 1212 repeatedly to make it 136136.The array is now [133,134,136,128,130,131][133,134,136,128,130,131].For this array, max(𝐴)−min(𝐴)=136−128=8max(A)−min(A)=136−128=8.It can be shown that this is optimal.
You are given an array a, of n elements. Find the minimum index based distance between two distinct elements of the array, x and y. Return -1, if either x or y does not exist in the array.
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.Given an array whose index represents houses and value at that index represents the size of that house.you have to find minimum cost for repairing . if the adjacent house size id smaller then the cost of repairing will always be higher than adjacent smaller house.
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