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.Given an array whose index represents houses and value at that index represents the size of that house.you have to find minimum cost for repairing . if the adjacent house size id smaller then the cost of repairing will always be higher than adjacent smaller house.

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.Given an array whose index represents houses and value at that index represents the size of that house.you have to find minimum cost for repairing . if the adjacent house size id smaller then the cost of repairing will always be higher than adjacent smaller house.

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Problem statementSend feedbackYou are given an array ‘A’ of length ‘N’. You say an index ‘i’ is beautiful if the sum of the first ‘i - 1’ elements of the array ‘A’ equals the sum of the last ‘N - i’ elements of the array ‘A’, where ‘i’ is in 1-based indexing. Now you wonder which is the leftmost beautiful index.Note: If you select the first index, then the sum of the prefix will be ‘0’, and if you select the last index, then the sum of the suffix will be ‘0’.Note: You have to print the index in 1-based indexing.For example:Let’s say the array ‘A’ = [1, 3, 1, 5], then if we select index ‘2’, the sum of the prefix is ‘1’, and the sum of the suffix is 1 + 5 = 6. Since the sum is not the same, hence index ‘2’ is not a beautiful index.Detailed explanation ( Input/output format, Notes, Images )Constraints -1 <= ‘T’ <= 101 <= ‘N’ <= 10^5 -10^9 <= A[i] <= 10^9, for 1 <= i <= ‘N’Note- Sum of ‘N’ over all test cases does not exceed 10^5.Time Limit: 1 secSample Input-1231 1 131 2 3Sample Output-12-1Explanation for Sample Input 1:For test case 1: Index ‘2’ is the leftmost beautiful index. The left sum is 1 and the right sum is also 1.For test case 2: No index is beautiful.Sample Input -2261 7 3 6 5 632 1 -1Sample Output -241

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