Knowee
Questions
Features
Study Tools

The following data give the energy needed to break the indicated bond. In the case of multiple bonds the energy applies to breaking the multiple bond completely:Bond Bond Dissociation EnergykJ/molBond Bond Dissociation EnergykJ/molC-H 413 C=O 745*C-C 347 C=C 614C-N 305 C≡C 839C-O 358 O=O 495O-H 463 N≡N 946N-H 391 C≡N 891 *C=O in carbon dioxide 804 kJ/molCalculate the energy required to dissociate all atoms, that is break all chemical bonds, in 1.00 mole of ammonia, NH3 .Question 3Select one:a.391 kJb.587 kJc.- 1173 kJd.- 391 kJe.1173 kJ

Question

The following data give the energy needed to break the indicated bond. In the case of multiple bonds the energy applies to breaking the multiple bond completely:Bond Bond Dissociation EnergykJ/molBond Bond Dissociation EnergykJ/molC-H 413 C=O 745*C-C 347 C=C 614C-N 305 C≡C 839C-O 358 O=O 495O-H 463 N≡N 946N-H 391 C≡N 891 *C=O in carbon dioxide 804 kJ/molCalculate the energy required to dissociate all atoms, that is break all chemical bonds, in 1.00 mole of ammonia, NH3 .Question 3Select one:a.391 kJb.587 kJc.- 1173 kJd.- 391 kJe.1173 kJ

...expand
🧐 Not the exact question you are looking for?Go ask a question

Solution

To calculate the energy required to dissociate all atoms in 1.00 mole of ammonia, NH3, we need to look at the bond dissociation energy for the N-H bond, which is given as 391 kJ/mol.

Ammonia (NH3) has three N-H bonds. Therefore, to break all these bonds in one molecule of NH3, the energy required would be 3 times the energy required to break one N-H bond.

So, the total energy required to break all bonds in 1.00 mole of NH3 would be 3 * 391 kJ/mol = 1173 kJ/mol.

Therefore, the correct answer is e. 1173 kJ.

This problem has been solved

Similar Questions

#06 bond makingThe following data give the energy needed to break the indicated bond. In the case of multiple bonds the energy applies to breaking the multiple bond completely. Bond formation, being the opposite, releases the same amount of heat from the chemical system.Bond Bond Dissociation EnergykJ/molBond Bond Dissociation EnergykJ/molC-H 413 C=O 745*C-C 347 C=C 614C-N 305 C≡C 839C-O 358 O=O 495O-H 463 N≡N 946N-H 391 C≡N 891 *C=O in carbon dioxide 804 kJ/molCalculate the heat released from the system on formation of 1.00 mol of the compound, methylamine CH3NH2, from its individual atoms, 1 mol C, 5 mol H and 1 mol N. C  +  5 H  + 1 N  →  CH3NH2  methylamineQuestion 4Select one:a.2304 kJb.1109 kJc.762 kJd.2326 kJe.2021 kJ

The bond energies are: C-H 416 kJ/mol; C-C 356 kJ/mol; C=C 598 kJ/mol; O=O 498 kJ/mol; C=O 803 kJ/mol; H-O 467 kJ/mol.The heat released or absorbed by the reaction is: _________Group of answer choices -8554 kJ/mol -3858 kJ/mol -4514kj/mol 4040 kJ/mol1270 kJ/mol PreviousNext

Calculate the energy required to break the bonds in propane (C3H8) given the following bond energies: C-C = 347 kJ/mol; C-H = 413 kJ/mol.

Breaking a chemical bond _____________ energy from the surroundings

Using the following data estimate the bond dissociation energy (BDE) of H-Cl: BDE (Cl-Cl)= 242kJ/ mol;BDE (H-H)= 434 kJ/mol; χp (Cl)= 3.2 and χp (H)=2.2 (1.0 eV = 96.5kJ/mol)

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.