Q1. 100g of water that is already at its boiling point, is boiled without any temperature change occurring. If the latent heat of vaporisation of water is 2260000J/kg, how much energy is needed to boil the water completely away?
Question
Q1. 100g of water that is already at its boiling point, is boiled without any temperature change occurring. If the latent heat of vaporisation of water is 2260000J/kg, how much energy is needed to boil the water completely away?
Solution
Step 1: Identify the given values. The mass (m) of the water is 100g, but we need it in kilograms for our calculations. So, m = 100g = 0.1kg. The latent heat of vaporisation (L) is given as 2260000J/kg.
Step 2: Use the formula for heat energy. The formula for heat energy (Q) required to change the state of a substance is Q = mL, where m is the mass of the substance and L is the latent heat of vaporisation.
Step 3: Substitute the given values into the formula. Q = 0.1kg * 2260000J/kg = 226000J
So, 226000 Joules of energy is needed to boil the water completely away.
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