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One of the type BB devices had a ball bearing of 4 mm in diameter. If the torque required to rotate the ball bearing prior to implantation was 1 µN·m, how much force was required?A.0.002 µNB.0.5 µNC.2 µND.500 µN

Question

One of the type BB devices had a ball bearing of 4 mm in diameter. If the torque required to rotate the ball bearing prior to implantation was 1 µN·m, how much force was required?A.0.002 µNB.0.5 µNC.2 µND.500 µN

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Solution

The torque (τ) is given by the equation τ = r * F, where r is the radius of the ball bearing and F is the force applied.

Given that the diameter of the ball bearing is 4 mm, the radius would be 2 mm or 0.002 m (since 1 m = 1000 mm).

The torque τ is given as 1 µN·m.

We can rearrange the equation to solve for F: F = τ / r.

Substituting the given values into the equation gives: F = 1 µN·m / 0.002 m = 500 µN.

So, the force required is 500 µN, which corresponds to option D.

This problem has been solved

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