Carbon monoxide reacts with oxygen to form carbon dioxide. 30.0  of carbon monoxide was reacted with 20.0  of oxygen.aCalculate the volume of carbon dioxide gas produced.

To solve this problem, we need to use the stoichiometry of the reaction. The balanced chemical equation for the reaction is:

2CO(g) + O2(g) -> 2CO2(g)

This tells us that two moles of carbon monoxide react with one mole of oxygen to produce two moles of carbon dioxide.

First, we need to convert the masses of CO and O2 to moles. The molar mass of CO is approximately 28.01 g/mol and the molar mass of O2 is approximately 32.00 g/mol.

So, the number of moles of CO is 30.0 g / 28.01 g/mol = 1.07 mol And the number of moles of O2 is 20.0 g / 32.00 g/mol = 0.625 mol

According to the stoichiometry of the reaction, we need two moles of CO for every mole of O2. We have more than enough CO, so O2 is the limiting reactant.

The reaction produces two moles of CO2 for every mole of O2, so we will produce 2 * 0.625 mol = 1.25 mol of CO2.

Finally, we need to convert this amount to a volume. At standard temperature and pressure (STP), one mole of any gas occupies 22.4 liters. So, the volume of CO2 produced is 1.25 mol * 22.4 L/mol = 28.0 L.