To solve this problem, we need to use stoichiometry, which is a method in chemistry that uses the relationship between reactants and products in a balanced chemical equation to answer the question.

Step 1: Write down the balanced chemical equation.
2C + O2 → 2CO

Step 2: Convert the given mass of oxygen to moles using its molar mass.
Given mass of O2 = 35.0 g
Molar mass of O2 = 32.00 g/mole
So, moles of O2 = 35.0 g / 32.00 g/mole = 1.09375 moles

Step 3: Use the stoichiometric ratio from the balanced chemical equation to find the moles of CO that can be formed.
From the balanced equation, we can see that 1 mole of O2 produces 2 moles of CO. So, 1.09375 moles of O2 will produce 2 * 1.09375 = 2.1875 moles of CO.

Step 4: Convert the moles of CO to grams using its molar mass.
Molar mass of CO = 28.01 g/mole
So, mass of CO = 2.1875 moles * 28.01 g/mole = 61.3 g

Therefore, 61.3 grams of CO can be formed from 35.0 grams of oxygen.

Question

To solve this problem, we need to use stoichiometry, which is a method in chemistry that uses the relationship between reactants and products in a balanced chemical equation to answer the question.

Step 1: Write down the balanced chemical equation.
2C + O2 → 2CO

Step 2: Convert the given mass of oxygen to moles using its molar mass.
Given mass of O2 = 35.0 g
Molar mass of O2 = 32.00 g/mole
So, moles of O2 = 35.0 g / 32.00 g/mole = 1.09375 moles

Step 3: Use the stoichiometric ratio from the balanced chemical equation to find the moles of CO that can be formed.
From the balanced equation, we can see that 1 mole of O2 produces 2 moles of CO. So, 1.09375 moles of O2 will produce 2 * 1.09375 = 2.1875 moles of CO.

Step 4: Convert the moles of CO to grams using its molar mass.
Molar mass of CO = 28.01 g/mole
So, mass of CO = 2.1875 moles * 28.01 g/mole = 61.3 g

Therefore, 61.3 grams of CO can be formed from 35.0 grams of oxygen.

Knowee AI · Accepted Answer

To solve this problem, we need to use stoichiometry, which is a method in chemistry that uses the relationship between reactants and products in a balanced chemical equation to answer the question.

Step 1: Write down the balanced chemical equation.
2C + O2 → 2CO

Step 2: Convert the given mass of oxygen to moles using its molar mass.
Given mass of O2 = 35.0 g
Molar mass of O2 = 32.00 g/mole
So, moles of O2 = 35.0 g / 32.00 g/mole = 1.09375 moles

Step 3: Use the stoichiometric ratio from the balanced chemical equation to find the moles of CO that can be formed.
From the balanced equation, we can see that 1 mole of O2 produces 2 moles of CO. So, 1.09375 moles of O2 will produce 2 * 1.09375 = 2.1875 moles of CO.

Step 4: Convert the moles of CO to grams using its molar mass.
Molar mass of CO = 28.01 g/mole
So, mass of CO = 2.1875 moles * 28.01 g/mole = 61.3 g

Therefore, 61.3 grams of CO can be formed from 35.0 grams of oxygen.

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