Calculate the voltage of a battery made up of four 3.6-V lithium-ion cells connected in series.32. A 100-W light bulb in a receptacle is supplied with electricity by a residential120-V circuit. This light bulb draws 0.833 A of current while it is on. Calculate theresistance of the light bulb.33. Describe how a circuit breaker reduces the risk of an electrical fire in a household electricalcircuit.31
Question
Calculate the voltage of a battery made up of four 3.6-V lithium-ion cells connected in series.32. A 100-W light bulb in a receptacle is supplied with electricity by a residential120-V circuit. This light bulb draws 0.833 A of current while it is on. Calculate theresistance of the light bulb.33. Describe how a circuit breaker reduces the risk of an electrical fire in a household electricalcircuit.31
Solution
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To calculate the voltage of a battery made up of four 3.6-V lithium-ion cells connected in series, you simply add up the voltage of each cell. This is because in a series circuit, the total voltage is the sum of the voltages across each component. So, 3.6V + 3.6V + 3.6V + 3.6V = 14.4V. Therefore, the voltage of the battery is 14.4V.
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To calculate the resistance of the light bulb, you can use Ohm's law, which states that the voltage (V) across a resistor is equal to the current (I) through it times its resistance (R). So, R = V/I. In this case, V = 120V and I = 0.833A. Therefore, R = 120V / 0.833A = approximately 144 ohms. Therefore, the resistance of the light bulb is approximately 144 ohms.
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A circuit breaker reduces the risk of an electrical fire in a household electrical circuit by automatically switching off the electrical supply when the current flowing through the circuit exceeds a certain level. This can happen if too many appliances are being used at once, or if there is a fault in the wiring. By cutting off the electricity, the circuit breaker prevents the wires from overheating and potentially causing a fire.
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