A person jumped out of a plane and began falling to the surface of the Earth at a rate of 9.8 m/s².The person and their equipment have a total mass of 95 kg.After 30 seconds they have reached a speed of 50 m/s.Calculate the kinetic energy store of the person and their equipment at this moment.KE = _____ J
Question
A person jumped out of a plane and began falling to the surface of the Earth at a rate of 9.8 m/s².The person and their equipment have a total mass of 95 kg.After 30 seconds they have reached a speed of 50 m/s.Calculate the kinetic energy store of the person and their equipment at this moment.KE = _____ J
Solution
To calculate the kinetic energy (KE) of the person and their equipment, we can use the formula for kinetic energy:
KE = 0.5 * m * v²
where: m is the mass (in kg) v is the velocity (in m/s)
Given in the problem, we know: m = 95 kg v = 50 m/s
Substituting these values into the formula gives us:
KE = 0.5 * 95 kg * (50 m/s)² KE = 0.5 * 95 kg * 2500 m²/s² KE = 0.5 * 237500 kg*m²/s² KE = 118750 J
So, the kinetic energy store of the person and their equipment at this moment is 118750 Joules.
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