Use the Hardy-Weinberg equations: p + q = 1 and p2 + 2pq + q2 = 1. If the dominant allele frequency is 0.8, what percentage of the population will be heterozygous?Multiple Choice32%16%64%4%20%
Question
Use the Hardy-Weinberg equations: p + q = 1 and p2 + 2pq + q2 = 1. If the dominant allele frequency is 0.8, what percentage of the population will be heterozygous?Multiple Choice32%16%64%4%20%
Solution
The Hardy-Weinberg equations are used to calculate the frequencies of alleles and genotypes in a population. The equations are p + q = 1 and p^2 + 2pq + q^2 = 1, where p is the frequency of the dominant allele, q is the frequency of the recessive allele, p^2 is the frequency of the homozygous dominant genotype, 2pq is the frequency of the heterozygous genotype, and q^2 is the frequency of the homozygous recessive genotype.
Given that the dominant allele frequency (p) is 0.8, we can calculate the recessive allele frequency (q) using the equation p + q = 1. Substituting p = 0.8 into the equation gives us q = 1 - 0.8 = 0.2.
We can then calculate the frequency of the heterozygous genotype (2pq) using the equation 2pq = 2 * 0.8 * 0.2 = 0.32 or 32%.
So, 32% of the population will be heterozygous.
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