Use the equation p2 + 2pq + q2 = 1.0 to solve the following problem. In a population of 100 squirrels there are 64 black ones, and the remaining are white. Black (B) is the dominant allele, and white (b) is the recessive allele. If the population is in Hardy-Weinberg equilibrium, what is the frequency of the black squirrels that are heterozygous (Bb) for their coat color?Multiple choice question.0.480.960.160.40
Question
Use the equation p2 + 2pq + q2 = 1.0 to solve the following problem. In a population of 100 squirrels there are 64 black ones, and the remaining are white. Black (B) is the dominant allele, and white (b) is the recessive allele. If the population is in Hardy-Weinberg equilibrium, what is the frequency of the black squirrels that are heterozygous (Bb) for their coat color?Multiple choice question.0.480.960.160.40
Solution
First, let's determine the frequency of the dominant allele (B) and the recessive allele (b).
The frequency of black squirrels (BB or Bb) is 64 out of 100, or 0.64. This is represented by p^2 + 2pq in the Hardy-Weinberg equation.
The frequency of white squirrels (bb) is 36 out of 100, or 0.36. This is represented by q^2 in the Hardy-Weinberg equation.
To find the frequency of the recessive allele (q), we take the square root of 0.36, which is 0.6.
Since p + q = 1, the frequency of the dominant allele (p) is 1 - 0.6 = 0.4.
The frequency of heterozygous black squirrels (Bb) is represented by 2pq in the Hardy-Weinberg equation.
So, 2pq = 2 * 0.4 * 0.6 = 0.48.
Therefore, the frequency of the black squirrels that are heterozygous (Bb) for their coat color is 0.48.
So, the answer is 0.48.
Similar Questions
For a gene with two alleles whose frequencies are p and q, the Hardy-Weinberg equation states that the genotypes that are possible for the population are p2 + 2pq + q2, which is equal to Blank______.Multiple choice question.(p + q)2p2 - q2p2 + q2q - p
Use the Hardy-Weinberg equations: p + q = 1 and p2 + 2pq + q2 = 1. If the dominant allele frequency is 0.8, what percentage of the population will be heterozygous?Multiple Choice32%16%64%4%20%
Which is a correct version of the Hardy-Weinberg equation for genotype frequencies in a population in equilibrium?Multiple choice question.p/q = 1p x 2pq x q = 1p2 + q2 = 1p2 + 2pq + q2 = 1
In a population of birds, the frequency of the recessive allele for feather coloration (a) is 0.25. Assuming the population is in Hardy-Weinberg equilibrium, calculate the following: The frequency of individuals heterozygous for the genotype (Aa).a.0.375b.0.5625c.0.0625d.0.9375
If the frequency of heterozygotes in a population of mice is 0.48 for a particular gene, what would be the frequency of heterozygotes in future generations if the population is in Hardy-Weinberg equilibrium?Multiple choice question.0.160.360.240.48
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.