!(4 %2  == 0) && ((8*2) > (3*3)) , is it true or false?Group of answer choicesTrueFalse

Let's break down the expression step by step:

1. 4 % 2 == 0: The modulus operator (%) gives the remainder of the division of two numbers. In this case, 4 divided by 2 has a remainder of 0, so 4 % 2 equals 0. Therefore, 4 % 2 == 0 is true.

2. (82) > (33): This is comparing whether 16 is greater than 9, which is true.

3. !(4 %2 == 0): The exclamation mark (!) is a logical NOT operator. It inverts the truth value of the expression that follows it. So, !(4 % 2 == 0) is false because 4 % 2 == 0 is true.

4. Finally, we have false && true. The logical AND operator (&&) returns true if both operands are true and false otherwise. In this case, it returns false.

So, the whole expression "!(4 %2 == 0) && ((82) > (33))" is false.