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A baseball team has to pick 9 players from a group of 20 players trying out.Howmany possible selections of players making the team are there?

Question

A baseball team has to pick 9 players from a group of 20 players trying out.Howmany possible selections of players making the team are there?

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Solution

The number of ways to select 9 players from 20 is a combination problem.

In mathematics, a combination is a selection of items without regard to the order. The formula for combinations is:

C(n, k) = n! / [k!(n-k)!]

where: n is the total number of items, k is the number of items to select, "!" denotes factorial, which is the product of all positive integers up to that number.

Substituting the given values into the formula, we get:

C(20, 9) = 20! / [9!(20-9)!]

= 20! / [9! * 11!]

This can be simplified by cancelling out the common factors in the numerator and the denominator:

= (20 * 19 * 18 * 17 * 16 * 15 * 14 * 13 * 12) / (9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1)

= 167,960

So, there are 167,960 possible selections of players making the team.

This problem has been solved

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