A person of mass 70 kg is connected by a rope at their waist to an anchor point on the building, where they remain stationary.What is the normal force acting on one of their feet? State your answer to two significant figures and give an appropriate unit.
Question
A person of mass 70 kg is connected by a rope at their waist to an anchor point on the building, where they remain stationary.What is the normal force acting on one of their feet? State your answer to two significant figures and give an appropriate unit.
Solution
To solve this problem, we need to understand that the normal force is the force exerted by a surface that supports the weight of an object resting on it. It acts perpendicular (normal) to the surface. The person in this problem is not accelerating, so the forces acting on them are balanced. This means the normal force should be equal to the person's weight.
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First, we need to calculate the weight of the person. Weight is calculated by multiplying the mass of an object by the acceleration due to gravity. On Earth, this acceleration is approximately 9.8 m/s². So, the weight of the person is 70 kg * 9.8 m/s² = 686 N (Newtons).
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Since the person is standing on two feet, we assume that the weight is evenly distributed between the two feet. Therefore, the normal force on one foot is half the total weight. So, the normal force on one foot is 686 N / 2 = 343 N.
Therefore, the normal force acting on one of the person's feet is 343 N.
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